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A child of mass m is released from rest at the top of a water slide,

at height h=8.8 m above the bottom of the slide. Assuming that the slide
is frictionless because of the water on it, find the child’s speed at the bottom of the slide

User DKK
by
3.8k points

1 Answer

2 votes

Answer:

From the concept of energy conservation, Ei=Ef

Step-by-step explanation:

mgh=1/2mv^2

=> v=

\sqrt{2gh}2gh

=

\sqrt{2 \times 9.8 \times 8.8}2×9.8×8.8

=

\sqrt{172.28}172.28

=13.12m/s.

User Pavel Tupitsyn
by
3.6k points