Question

1. Two forces F~

1 and F~
2 are acting on a block of mass m=1.5 kg. The magnitude of
force F~
1 is 12N and it makes an angle of θ = 37◦ with the horizontal as shown in
figure-1. The block is sliding at a constant velocity over a frictionless floor.
Figure-1
(a) Find the value of the normal force on the block.
[3 marks]
(b) Find the magnitude of force F~
2 that is acting on the block
[4 marks]
(c) Find the magnitude of force F~
2 if the block accelerates with a magnitude of
a = 2.5 m/s2 along the direction of F~
2 . [3 mark

Answer 1

(a) Normal force=7.48 N

Step-by-step explanation:

N+F~1 sinθ-mg=0

=>N=1.5*9.8-12 sin37◦

=>N=14.7-7.22=7.48 N