Question

S= √3+2√3+3√3+...10√3
write S as a√3

Answer 1

s=✓3(1+2+3+...10)

s=✓3[10/2×(10+1)]

here, applying sum of 1st n natural number is n/2×(n+1)

so, s=✓3×5×11

hence, s=55✓3.

Answer 2

• S = 55√3

Explanation:

S=

• √3+2√3+3√3+...10√3 =
• √3( 1 + 2 + 3+...+ 10) =
• √3(1/2)(10)(10 + 1) =
• √3(55) =
• 55√3

S = 55√3