Question 6
Given the points
Finding the slope between (-2, 1) and (-3, -3)




Question 7
Given the points
Finding the slope between (-4, 3) and (-2, -1)




Question 8
Given the points
Finding the slope between (0, -2) and (0, -4)
As we know that the slope of the line given by the equation x=0 is undefined.




= ∞