Question

given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.​

Answer 1

The balanced condition for Wheat stones bridge is

Q

P

​

=

S

R

​

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R

1

​

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R

2

​

=R+S

=20+30=50Ω

Net resistance of the network as R

1

​

and R

2

​

are in parallel

i=

R

V

​

=

50

6×3

​

=0.36 A.

Step-by-step explanation: