Answer:
0.02 mol
Step-by-step explanation:
Given data:
Number of moles of nitrogen = ?
Volume of sample = 400 cm³
Pressure = 790 mmHg
Temperature = 27°C
Solution:
Volume of sample = 400 cm³ (400/1000=0.4 L)
Pressure = 790 mmHg (790/760 = 1.04 atm)
Temperature = 27°C (27+273=300 K)
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1.04 atm ×0.4 L = n× 0.0821 atm.L/ mol.K ×300 K
0.416 atm.L = n× 24.63 atm.L/ mol
n = 0.416 atm.L /24.63 atm.L/ mol
n = 0.02 mol