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Pls can someone help me factorise: 4u²‐u-3

User Tom Beech
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1 Answer

4 votes

Answer:

(u - 1)(4u + 3)

Explanation:

Given

4u² - u - 3

Consider the factors of the product of the coefficient of the u² term and the constant term which sum to give the coefficient of the u- term.

product = 4 × - 3 = - 12 and sum = - 1

The factors are - 4 and + 3

Use these factors to split the u- term

4u² - 4u + 3u - 3 ( factor the first/second and third/fourth terms )

= 4u(u - 1) + 3(u - 1) ← factor out (u - 1) from each term

= (u - 1)(4u + 3)

Thus

4u² - u - 3 = (u - 1)(4u + 3) ← in factored form

User Lenniep
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