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A 10.0 kg box is dragged 5.00 meters across a rough horizontal floor by a rope with a tension

of 45.0 N that makes an angle of 20.0 degrees to the horizontal. If the box started with a
speed of 3.00 m/s and ended with a speed of 5.00 m/s, what was the NET work done on the
box?

1 Answer

5 votes

Answer:

Step-by-step explanation:

Net work done on the box = increase in kinetic energy

= 1 / 2 x 10 ( 5² - 3² )

= 80 J .

User Andyengle
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