Question

A varies inversely as the square of B. If A is 1 when B is 3, find A when B is 5

Answer 1

0.36

Explanation:

A= K/B^2

K= A × B^2

K= 1 × 3^2

K= 1×9

K= 9

Therefore if B is 5 then A can be calculated as follows.

K= A × B^2

9= A × 5^2

9= A × 25

9= 25A

A= 9/25

A= 0.36

Hence A is 0.36