Question

What is an equation of the line that passes through the points (−6,−2) and (6, 8)

Answer 1

Answer:
`y=(5)/(6)x+3`

Explanation:

To find the equation of the line with the given points, we want to first find the slope then the y-intercept. We use the formula
`m=(y_2-y_1)/(x_2-x_1)`.

`m=(8-(-2))/(6-(-6)) =(10)/(12)=(5)/(6)`

Now that we know the slope, we can use one of the points to find the y-intercept.

`8=(5)/(6)(6)+b` [multiply]

`8=5+b` [subtract both sides by 5]

`b=3`

Now, we know the equation is
`y=(5)/(6)x+3`.