Question

During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25s. What is the sprinter’s average acceleration during this period?

Answer 1

Answer: 2 m/s^2

Explanation: Hope this helps :)

Answer 2

`\boxed {\boxed {\sf 2 \ m/s^2}}`

Step-by-step explanation:

Acceleration can be found by dividing the change in velocity by the time.

`a=(\Delta v)/(t)`

The time is 1.25 seconds. The change in velocity is the difference between the initial velocity and the final velocity.

• 
  `\Delta v=v_f-v_i`
• The final velocity is 7.5 m/s and the initial velocity is 5.0 m/s
• 
  `\Delta v =7.5 \ m/s-5.0 \ m/s=2.5 \ m/s`

`\Delta v= 2.5 \ m/s\\t=1.25 \ s`

Substitute the values into the formula.

`a=(2.5 \ m/s)/(1.25 \ s)`

Divide.

`a=2 \ m/s^2`

The sprinter's average acceleration is 2 meters per second squared.