Answer:
Solving this system of linear equations by elimination we get x=-1 and y=-2
Option 1 is correct option.
Explanation:
We are given equations:
![y=x-1---eq(1)\\2x-y=0---eq(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vsg7e4i295sl79letjyau6eogs9afkm4cz.png)
We need to solve by Elimination method.
Elimination method: Add or subtract the equations to get an equation in one variable.
Rearranging the equation 1 we get
![-x+y=-1---eq(1)\\2x-y=0---eq(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/el58bzhnhx76nod24qwi8ptjfoif4dlro2.png)
Add eq(1) and eq(2)
![-x+y=-1\\2x-y=0\\------\\x=-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/befgdn42tubhizkpu3ix7awxvgrb9xey05.png)
So, after eliminating y we get x=-1
Now finding y by putting x in eq(1)
![y=x-1\\y=-1-1\\y=-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/cygk0yqnlljyfameovi2xllv5jt01n4lok.png)
We get y=-2
So, solving this system of linear equations by elimination we get x=-1 and y=-2
Option 1 is correct option.