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Find if the series converges conditionally, converges absolutely, or diverges ∑k=1 ∞ (k^2k 3^k)/k!

Find if the series converges conditionally, converges absolutely, or diverges ∑k=1 ∞ (k^2k 3^k)/k!
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Find if the series converges conditionally, converges absolutely, or diverges ∑k=1 ∞ (k^2k 3^k)/k!

User Nikit Batale
by
8.4k points

1 Answer

2 votes

Answer:

Diverges

Explanation:

Using the ratio test to test the series:

Find if the series converges conditionally, converges absolutely, or diverges ∑k=1 ∞ (k-example-1
User Galaxy
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