Answer:
89.6 L
Step-by-step explanation:
In normal conditions,
For every 1 mole of carbon dioxide at STP, it occupies 22.4 L of volume.
============================================================
Solving :
⇒ 1 mole : 22.4 L
⇒ 1 × 4 : 22.4 × 4
⇒ 4 moles : 89.6 L