Answer:
1. V = 1.47L
Step-by-step explanation:
1) Using PV = nRT
Where;
P = pressure (atm)
V = volume (L)
R = gas constant (0.0821 Latmk mol)
n = number of moles
T = temperature (K)
To get number of moles, we say mole = mass/molar mass
Molar Mass of C2H2 = 12(2) + 1(2)
= 24 + 2 = 26g/mol
mole = 3.86/26
mole = 0.148mol
T (K) = 28.5°C + 273.15
T(K) = 301.65K
PV = nRT
2.5 × V = 0.148 × 0.0821 × 301.65
2.5V = 3.665
V = 3.665/2.5
V = 1.466
V = 1.47L
R =
PV = nRT
P1 V1\ n1 T1 =P2 V2/ n2 T2
1. What volume, will be occupied by 3.86 g of C2H2 gas (acetylene) at 2.50 atm and a temperature
of 28.5 °C?
2. A gas at 650.0 torr and 75 °C is cooled to 25 °C. What is the pressure of the gas after it has
cooled?