Question

12. F(x) = 4x squared

Answer 1

y-intercept:
`y=0`

axis of symmetry:
`x=0`

vertex:
`(0,0)`

Explanation:

To find the y-intercept, set x = 0 and solve for y.

I am assuming f(x) = y

`y=4x^2`

`y=4(0)^2`

`y=0`

The y-intercept of the equation is y = 0.

Now, for the axis of symmetry, you need the equation
`x=(-b)/(2a)`

In an equation..
`y=ax^2+bx+c`

In this case, there is only an a, so plug in the values into the equation.

`x=(0)/(2(4))`

`x=0`

The axis of symmetry is x = 0.

To find the vertex, change the format of the equation from standard form to vertex form.

Vertex form:
`y=a(x-h)^2+k`

The vertex is
`(h,k)`

`y=4x^2 = 4(x+0)^2+0`

`(h,k)=(0,0)`

The vertex in this case is (0,0).

Graphing makes things a lot easier. If you can graph it, all you have to do is look at the graph and the answers are all there!

Hope this helped you!