Question

A balloon contains 3.20 L of helium. The pressure is reduced to 59.0 kPa, and the

balloon expands to occupy a volume of 5.50 L. What was the initial pressure exerted on
the balloon?

Answer 1

101.4pKa

Step-by-step explanation:

Given parameters:

Initial Volume of helium = 3.20L

Final pressure of helium = 59kPa

Final volume on helium gas = 5.5L

Unknown:

Initial pressure exerted on the balloon = ?

Solution;

To solve this pressure - volume problem, we simply apply the Boyle's law.

It states that "the volume of a fixed mass gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

P1 V1 = P2 V2

Now, insert parameters and solve;

P1 x 3.2 = 59 x 5.5

P1 = 101.4pKa