Question

An object starts from rest at the origin and moves along the x axis with a constant

acceleration of 4 m/s

2

. Its average velocity as it goes from x = 2 m to x = 8 m is:​

Answer 1

6.9m/s

Step-by-step explanation:

Given parameters:

Acceleration of the object = 4m/s²

Distance = from x; 2m to x; 8m

Unknown:

Average velocity = ?

Solution:

From the given parameters, we use the right motion equation to solve the problem.

v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance covered

Distance = 8m - 2m = 6m

Initial velocity = 0m/s

The final velocity gives us the average velocity in this problem;

v² = 0² + (2 x 4 x 6) = 48

v = √48 = 6.9m/s