Question

Suppose 100 ml of hydrochloric acid is neutralized by exactly 46.9ml of 0.75M lithuim hydroxide . What is the concentration of the hydrochloric acid?

Answer 1

0.0035M

Step-by-step explanation:

Given parameters

Volume of HCl = 100mL = 0.1L

Volume of LiOH = 46.9mL = 0.0469L

Molarity of LiOH = 0.75M

Unknown:

Concentration of hydrochloric acid = ?

Solution:

The reaction equation is given as;

HCl + LiOH → LiCl + H₂O

Let us find the number of moles of the given specie which is LiOH;

Number of moles = molarity x volume;

Number of moles of LiOH = 0.75 x0.0469 = 0.035moles

From the balanced reaction equation;

1 mole of LiOH combines with 1 mole of HCl

0.035mole of LiOH will require 0.035mole of HCl

Concentration of HCl =
`(number of moles of HCl)/(volume of HCl)`

Concentration of HCl =
`(0.035)/(0.1)` = 0.0035M