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Titus is asked to prove hexagon FEDCBA is congruent to hexagon

F'E'D'C'B'A' in the graph below. Titus thinks that if he transforms hexagon
FEDCBA by (x, y) = (x + 16, y - 10) he can show the two figures are
congruent. Is he correct? Explain why or why not. If Titus is incorrect, what
series of transformations will correctly prove FEDCBA – FEDCBA?

Is Titus correct? YES
Explain why

Titus is asked to prove hexagon FEDCBA is congruent to hexagon F'E'D'C'B'A' in the-example-1
User FuriousD
by
5.4k points

1 Answer

5 votes

Answer:

(x, y) -------> ( - x , y - 10 )

Explanation:

Titus is not correct.

There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'

First transformation is Reflection over y-axis , then translation 10 units down.

The final formula is ( - x , y - 10 )

User Hardian
by
4.9k points
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