Question

How many molecules (or atoms) of tin (IV) nitrate would contain 6.17 moles of
oxygen atoms?

Answer 1

3.01 x 10²³ molecules

Step-by-step explanation:

Given parameters:

Number of moles of oxygen atoms = 6.17moles

Unknown:

Number of molecule of tin(IV) nitrate = ?

Solution:

To solve this problem, let us write the formula of tin (IV) nitrate;

N₄O₁₂Sn

Now,

12 moles of Oxygen can be found in 1 mole of N₄O₁₂Sn

6.17 moles of oxygen will be found in
`(6.17)/(12)` = 0.5mole of N₄O₁₂Sn

So;

1 mole of a substance contains 6.02 x 10²³ molecules

0.5 mole of N₄O₁₂Sn will contain 0.5 x 6.02 x 10²³ = 3.01 x 10²³ molecules