Question

In triangle OPQ, p = 38 cm, q = 29 cm and Angle O=39º. Find the length of o, to the nearest

centimeter.

Answer 1

The length of o is 24 centimeters

Explanation:

In Δ OPQ

∵ Side p is opposite to ∠P

∵ Side q is opposite to ∠Q

∵ Side o is opposite to ∠O

→ To find side o we must use the cosine rule

∴ o =
`\sqrt{p^(2)+q^(2)-2(p)(q).cos(O) }`

∵ p = 38 cm

∵ q = 29 cm

∵ m∠O = 39°

→ Substitute them in the rule to find o

∴ o =
`\sqrt{(38)^(2)+(29)^(2)-2(38)(29).cos(39)}`

∴ o = 23.92008154

→ Round it to the nearest centimeter (whole number)

∴ o = 24 centimeters

∴ The length of o is 24 centimeters