Answer:
the answer is B
Step-by-step explanation:
we assume that all of these springs have tha same k , the spring constant
elastic energy for the initial system = Ep1=

for the new changed system , the spring constant = k1+k2 = k+k = 2k , but the displacement is also reduced to 0.5 d
so Ep2 =
so the new total Ep stored in the new system is 1/2Ep
hope it helps