Question

Find the equation of a straight line passing through the point (0,1) which is perpendicular to the line y=-2x+2

Answer 1

y =
`(1)/(2)` x + 1

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 2 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-2)` =
`(1)/(2)`

The line crosses the y- axis at (0, 1) ⇒ c = 1 , then

y =
`(1)/(2)` x + 1 ← equation of perpendicular line