Question

how many grams of sodium hydroxide are required to dissolve in 232 g of water to make a 2.88 m solution

Answer 1

Grams of Sodium hydroxide : 26.72 g

Further explanation

Molality shows the number of moles dissolved in every 1000 grams of solvent.

m = n. (1000 / p)

m = Molality

n = Number of moles of solute

p = Solvent mass (gram)

Can be written :

`\tt m=(mol~solute)/(kg~solvent)`

• mol solute(NaOH)

m=2.88

kg solvent(water)=232 g=0.232 kg

`\tt mol~solute=m* kg~solvent\\\\mol~solute=2.88* 0.232=0.668`

• mass of NaOH

`\tt mass=mol* MW\\\\mass=0.668* 40~g/mol=26.72~g`