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Divide (- 6 + i)/(1 - 2i) =

User ARZMI Imad
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(-6+i)/(1-2i)=((-6+i)(1+2i))/((1-2i)(1+2i))=(-6-12i+i-2)/(1+4)=(-8-11i)/(5)=-(8)/(5)-(11)/(5)i

User Jared Barden
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~~~((-6 +i))/((1- 2i))\\\\\\=((-6+i)(1+2i))/((1-2i)(1+2i))\\\\\\=(-6-12i+i+2i^2)/(1-(2i)^2)\\\\\\=(-6-11i-2)/(1+4)~~~~~~~~~~~~~;[i^2=-1]\\\\\\=(-8-11i)/(5)\\\\\\=-\frac 85-(11)/(5)i

User Seeingidog
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