Answer:
m∠1 = 63°
m∠2 = 49°
m∠3 = 87°
m∠4 = 44°
Explanation:
From the given figure
∵ ∠2 and 49° are vertically opposite angles
∵ The vertical opposite angles are equal in measures
∴ m∠2 = 49°
∵ The sum of the interior angles of a Δ is 180°
∵ m∠1, m∠2, and 68° are interior angles of a Δ
∴ m∠1 + m∠2 + 68° = 180°
∵ m∠2 = 49°
∴ m∠1 + 49° + 68° = 180°
→ Add the like terms in the left side
∴ m∠1 + 117 = 180
→ Subtract 180 from both sides
∴ m∠1 = 63°
∵ ∠3 and 93° formed a pair of linear angles
∵ The sum of the measures of the linear angles is 180°
∴ m∠3 + 93° = 180°
→ Subtract 93 from both sides
∴ m∠3 = 87°
∵ 93° is an exterior angle of the triangle
∵ The measure of the exterior angle of a Δ at one vertex equals the sum
of the measures of the opposite interior angles to this vertex
∵ ∠4 and 49° are the opposite interior angles to 93°
∴ 49° + m∠4 = 93°
→ Subtract 49 from both sides
∴ m∠4 = 44°