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Given the circumference of equation
\bf{x^(2)+y^(2)-2x+4y-4=0}, find the center and the radius.

User Armatorix
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1 Answer

8 votes

We will convert the general equation to the ordinary form \left
\bf{( x-h \right )^(2)+\left ( y-k \right )^(2)=r^(2)}; For this we follow the following steps:

We rewrite the equation by ordering the x and y and we complete the perfect square trinomials:


\bf{x^(2)-2x+1+y^(2)+4y+4=4+1+4 }

Factor the perfect square trinomials:


\bf{(x-1)^(2)+(y+2)^(2)=9 }\\\bf{ \ \ \ \ \Rightarrow \ C(1,-2) y \ r=3 }

User Sharrod
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