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Write the balanced equation for the reaction that occurs when aluminum bromide is mixed with potassium sulfate forming potassium bromide and aluminum sulfate

User Sugan S
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Answer:

2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃

Step-by-step explanation:

Given species;

Reactants

Aluminum bromide = AlBr₃

Potassium sulfate = K₂SO₄

Products

Potassium bromide = KBr

Aluminum sulfate = Al₂(SO₄)₃

So, the reaction equation is given as:

AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃

To balance this chemical equation, let us an algebraic approach;

aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃

Conserving Al;

a = 2d

Conserving Br;

3a = c

Conserving K;

2b = c

Conserving S;

b = 3d

Conserving O;

4b = 12d

if a = 1;

c = 3

b =
(3)/(2)

d =
(1)/(2)

Now, multiply through by 2;

a = 2, b = 3, c = 6 and d = 1

2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃

User KiwiMartin
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