Question

What is the difference in KE between a 52.5 kg person running 3.50 m/s and a 0.0200 kg bullet flying 450 m/s?

(Unit = J)

Answer 1

Answer: 1703.44

Explanation: trust

Answer 2

Ek = 1705.28 [J]

Step-by-step explanation:

In order to solve this problem, we must remember that kinetic energy can be calculated by means of the following equation.

`E_(k)=(1)/(2) *m*v^(2)`

where:

m = mass [kg]

v = velocity [m/s]

Ek = kinetic energy [J] (Units of Joules)

For the person running

`E_(k) =(1)/(2)*52.2*(3.5)^(2) \\ E_(k) =319.72[J]`

For the bullet

`E_(k) =(1)/(2) *m*v^(2)`

`E_(k) =(1)/(2) *0.02*(450)^(2) \\E_(k)=2025 [J]`

The difference in Kinetic energy is equal to:

Ek = 2025 - 319.72

Ek = 1705.28 [J]