Answer:
The coordinates of the image of B(-3, -2) is B'(3, -2).
Explanation:
- We know that when a point (x, y) is reflected across the y-axis, the y-coordinate remains the same, and then the x-coordinate becomes negative.
i.e.
- Thus, the image of P(x, y) is P' (-x, y).
Given the point
Hence, the image of B(-3, -2):
- (-x, y) → (-(-3), -2) = (3, -2)
Therefore, the coordinates of the image of B(-3, -2) is B'(3, -2).