HELP PLS this is my last question

Question

asked Sep 22, 2021 142k views

1 Answer

Lbergnehr · Answer 1 · 2021-09-27T11:28:16+0000

Answer:

The solutions to the system of the equations are:

$y=1,\:x=3$

Explanation:

Given the equations

$y=(2)/(3)x-1;\:y=-x+4$

solving the system of equation

$\begin{bmatrix}y=(2)/(3)x-1\\ y=-x+4\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}y-(2)/(3)x=-1\\ y+x=4\end{bmatrix}$

y+x=4

$\underline{y-(2)/(3)x=-1}$

(5)/(3)x=5

$\begin{bmatrix}y-(2)/(3)x=-1\\ (5)/(3)x=5\end{bmatrix}$

solving for x

(5)/(3)x=5

5x=15

Divide both sides by 15

(5x)/(5)=(15)/(5)

x=3

$\mathrm{For\:}y-(2)/(3)x=-1\mathrm{\:plug\:in\:}x=3$

$y-(2)/(3)\cdot \:3=-1$

y-2=-1

Add 2 to both sides

y-2+2=-1+2

y=1

Therefore, the solutions to the system of the equations are:

$y=1,\:x=3$