Question

Write an equation in point-slope form, slope intercept form, and standard form for a line that passes through (-2,8) with slope 8/5

please help :(((( don’t give answers if you aren’t sure

Answer 1

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Answer:

• y -8 = 8/5(x +2)
• y = 8/5x +56/5
• 8x -5y = -56

Explanation:

Since you're given a point and slope, it is convenient to start with that form.

Point-slope form

y -k = m(x -h) . . . . . line with slope m through point (h, k)

y -8 = 8/5(x +2) . . . point-slope equation

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Slope-intercept form

y = mx + b . . . . . line with slope m and y-intercept b

The above equation can be rearranged to this form.

y = 8/5x +16/5 +8

y = 8/5x +56/5 . . . . . slope-intercept form

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Standard form

ax +by = c

Multiplying by 5 and subtracting the y-term gives the general form equation ...

5y = 8x +56

8x -5y +56 = 0

8x -5y = -56 . . . . . . add -56 to put into standard form