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Which function has a range of (-pi/2,pi/2)? y = Cos-1x y = Tan-1x y = Sec-1x y = Csc-1x
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Which function has a range of (-pi/2,pi/2)?

y = Cos-1x
y = Tan-1x
y = Sec-1x
y = Csc-1x

User Sebastian Wozny
by
7.7k points

1 Answer

4 votes

Answer:

b) y=tan^-1(x)

Explanation:

edge 2020

User Radamanthus
by
7.4k points
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