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Solve tan x =cot x for 0 < x < pi

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tan(x) = cot(x)

tan(x) = 1 / tan(x)

tan²(x) = 1

tan²(x) - 1 = 0

(tan(x) - 1) (tan(x) + 1) = 0

tan(x) - 1 = 0 or tan(x) + 1 = 0

tan(x) = 1 or tan(x) = -1

x = π/4 + or x = -π/4 +

where in both cases, n is any integer.

In the interval 0 < x < π, we get solutions:

x = π/4 from the first family (when n = 0)

x = 3π/4 from the second family (when n = 1)

So the equation has solutions x = π/4 or x = 3π/4.

User Saeed Zarinfam
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