Answer:
A) the curves are ellipses
B) 161 yards
C) 366 yards
Step-by-step explanation:
A) The general shape of the side marked c has the appearance of two quarter-ellipses. The major axis is approximately 125 yards, and the minor axis is approximately 80 yards. Paul could assume that the curves are quarter-ellipses.
B) For an ellipse with this eccentricity, its perimeter is within 2% of that of a circle with a diameter equal to the average of these dimensions.*
So, the approximate length of side c is ...
c ≈ π(80 +125)/4 ≈ 161 . . . . yards; length of side c
C) The perimeter of the pond is the sum of the side lengths, so will be ...
80 yds + 125 yds + 161 yds = 366 yds . . . pond perimeter
Indian mathematician Ramanujan developed an approximate formula for the circumference of an ellipse, which would otherwise need to be computed using an elliptic integral. it is ...
C = π(a+b)(1 + 3λ²/(10 +√(4 -3λ²)) where λ = (a -b)/(a +b) and a, b are the semi-axis lengths.
For this ellipse, λ = 9/41, so the last factor is about 1.01208313. Using this factor, the circumference is expected to be good to about 7 significant digits. Continuing the calculation, we find C ≈ 325.904 . . . . circumference of an ellipse 125 yd long by 80 yd wide
This is twice the length we imagine for c, so c ≈ 163 yards. As we said, the approximation used above is within 2% of this value.
The attachment shows the shape if the curve is actually an ellipse.