Answer:
3,645.7m
Explanation:
The set up will give a right angled triangle;
altitude (opposite side ) = 1700m
angle of depression = 25degrees
Required
distance from the plane to the rock (adjacent side)
Using the SOH, CAH, TOA identity;
According to TOA
tan 25 = opposite/adjacent
tan25 = 1700/adj
adj = 1700/tan 25
adj = 1700/0.4663
adj = 3,645.72m
Hence the distance from the plane to the rock to 1 dp is 3,645.7m