Answer: 1/6
Explanation:
Probability of getting heads or tail is:
P (H) = P(T) = 1/2
The probability of getting any number on the die is:
P (1) = P (2) = P(3) = P (4) = P (5) = P (6) = 1/6
The probability of getting a tail on the coin and a number less than 3 on the die is:
![P($Tails and a number less than 3$)=P($Tails$) * P$(A number less than 3)$$\begin{aligned}&=(1)/(2) *[P(1)+P(2)] \\&=(1)/(2) *\left[(1)/(6)+(1)/(6)\right] \\&=(1)/(6)\end{aligned}$$](https://img.qammunity.org/2023/formulas/mathematics/high-school/dbwih1xjlnculjmatc3e03jok3unw2p0ny.png)
Therefore the required of getting tails and a number less than 3 is 1/6