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Given lines p and q are parallel, m<2 - (14x - 12), m<6 - (5y + 23), and m<8 - (8x + 27), solve for the values of x and y then solve for the measure of each angle

Given lines p and q are parallel, m<2 - (14x - 12), m<6 - (5y + 23), and m&lt-example-1
User Diggy
by
5.3k points

1 Answer

1 vote

Answer:

x = 7.5

y = 14

m<1 = 87°

m<7 = 93°

Explanation:

Given:

m<2 = (14x - 12),

m<6 = (5y + 23),

m<8 = (8x + 27)

m<2 + m<8 = 180° (consecutive exterior angles are supplementary)

(14x - 12) + (8x + 27) = 180 (substitution)

Solve for x

14x - 12 + 8x + 27 = 180

Collect like terms

22x + 15 = 180

Subtract 15 from each side

22x = 180 - 15

22x = 165

Divide both sides by 22

x = 7.5

m<2 = m<6 (corresponding angles are congruent)

(14x - 12) = (5y + 23) (substitution)

Plug in the value of x

14(7.5) - 12 = 5y + 23

105 - 12 = 5y + 23

93 = 5y + 23

Subtract 23 from each side

93 - 23 = 5y

70 = 5y

Divide both sides by 5

14 = y

y = 14

✅m<1 = m<8 (alternate exterior angles are congruent)

m<1 = (8x + 27) (substitution)

Plug in the value of x

m<1 = 8(7.5) + 27 = 87°

m<7 = m<2 (alternate exterior angles are congruent)

m<7 = (14x - 12) (substitution)

Plug in the value of x

m<7 = 14(7.5) - 12 = 93°

User Shahrooz Ansari
by
4.9k points
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