Question

Oh gosh I dunno any of this-

Trigonometry

Answer 1

You need to use SOHCAHTOA.
Sin (opposite/hypotenuse)
Cos (adjacent/hypotenuse)
Tan (opposite/adjacent)

For the first photo, you would use
Tan( opposite/adjacent)
4/x = tan(20)
Then you just change the equation to have x on the side by itself.
(4)(tan20) = x
Then write that into the calculator.

For the second problem, you use
Sin(opposite/hypotenuse)
Sin(25)=x/10
Change the equation to have x by itself.
Sin(25)(10)=x
Then plug it into the calculator.

Answer 2

Step-by-step explanation:

Triangle 1:

Problem:

Find leg
`a` of a right triangle if hypotenuse
`c=10` and angle
`\alpha =25^o`.

Solution:

`a` ≈
`4.2262`

Step-by-step explanation:

To find leg
`a` use formula:

`\text{sin}(\alpha )=(a)/(c)`

After substituting
`\alpha =25^o` and
`c=10` we have:

`sin(25^o)=(a)/(10)\\0.4226=(a)/(10)\\a=0.4226*10\\`

`a=4.2262`

Triangle 2:

Problem:

Find leg
`b` of a right triangle if leg
`a=4` and angle
`\alpha =20^o`.

Solution:

`b` ≈
`10.9899`

Step-by-step explanation:

To find leg
`b` use formula:

`\text{tan}(\alpha)=(a)/(b)`

After substituting
`\alpha =20^o` and
`a=4` we have:

`tan(20^o)=(4)/(b)\\0.364=(4)/(b)\\b=(4)/(0.364)\\b =10.9899`