78.6k views
2 votes
There is a spinner with 12 equal areas, numbered 1 through 12.. If the spinner is spun once, what is the probability that the result is a multiple of 3 or a multiple of 4

User Mathter
by
7.9k points

1 Answer

5 votes

Answer:


(1)/(2)

Explanation:

Given that, spinner has 12 equal areas, so there are 12 possibilities of occurrences i.e. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

Multiples of 3 are: {3, 6, 9, 12}

Multiples of 4 are: {4, 8, 12}

To find the multiple of 3 or 4, we need to find the union of the above two sets.

Multiples of 3 or 4: {3, 4, 6, 8, 9, 12}

Number of multiples of 3 or 4 = 6

Formula for probability of an event E can be observed as:


P(E) = \frac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, number of favorable cases are 6 and

Total number of cases are 12.

Therefore the required probability is:


P(\text{Multiple of 3 or 4}) = (6)/(12)\\P(\text{Multiple of 3 or 4}) = \bold{(1)/(2)}

User Calimo
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories