Question

A proton moves at a speed of 850 m/s in a direction perpendicular to a magnetic field with a magnitude of 0.70 T. What is the magnitude of the magnetic force on the proton?

Answer 1

The magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N

Step-by-step explanation:

Given;

speed of proton, v = 850 m/s

magnitude of magnetic field, B = 0.7 T

Charge of proton, q = 1.602 x 10⁻¹⁹ C

The magnitude of the magnetic force on the proton;

F = qvB

F = ( 1.602 x 10⁻¹⁹)(850)(0.7)

F = 9.532 x 10⁻¹⁷ N.

Therefore, the magnitude of the magnetic force on the proton is 9.532 x 10⁻¹⁷ N