Question

An object is thrown with a horizontal velocity of 49mt/sec and a vertical velocity of 18.8 mt/sec. How long will the object take to return to earth. Please help asap

Answer 1

The object takes 3.84 seconds to return to earth.

Step-by-step explanation:

Projectile Motion

It's when an object projected above the ground at a certain velocity, moves along a curved path under the action of gravity.

The initial velocity has two components, given by:

`v_x=vo_x`

`v_y=vo_y-gt`

Where vox is the initial component of the velocity in the horizontal direction, voy is the initial component of the velocity in the vertical direction, and t is the time.

The object reaches a maximum height and then it returns to the ground. The time it takes to reach the maximum height can be calculated when the vertical component of the velocity is zero:

`vo_y-gt=0`

`\displaystyle t_m=(vo_y)/(g)`

The initial vertical component of the velocity is 18.8 m/s, thus:

`\displaystyle t_m=(18.8)/(9.8)=1.92~s`

The total time is double that time:

`t_t=2*1.92~s=3.84~s`

The object takes 3.84 seconds to return to earth.