Question

What volume of a 0.311 M hydrochloric acid solution is required to neutralize 13.9 mL of a 0.110 M potassium hydroxide solution?

Answer 1

4.9 mL

Step-by-step explanation:

To answer this question we will use the following equation:

• C₁V₁=C₂V₂

Where the subscript 1 refers to hydrochloric acid, while 2 refers to potassium hydroxide. Meaning:

• C₁ = 0.311 M

• V₁ = ?

• C₂ = 0.110 M

• V₂ = 13.9 mL

So we solve for V₁:

• 0.311 M * V₁= 0.110 M * 13.9 mL

• V₁ = 4.9 mL