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A solid object is dropped into a pond with a temperature of 20 degrees Celsius. The function f(t) = Ce(-kt) + 20 represents the situation where t is time in minuetes, C is a constant and k = 0.0399. After 4 minutes the object has a temperature of 35 degrees Celsius. What was the initial temperature of the object

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Given :

A solid object is dropped into a pond with a temperature of 20 degrees Celsius.

The function f(t) = Ce(-kt) + 20 represents the situation where t is time in minutes, C is a constant and k = 0.0399.

To Find :

The initial temperature of the object.

Solution :

Putting t = 4 in given equation, we get :


35 = Ce^((-0.0399)* 4))+20\\\\15 = Ce^(-0.16)\\\\C = 15* e^(0.16)\\\\C = 17.60

Putting value of C in given equation, we get :


f(t) = 17.60e^(-0.0399t) + 20

Now, for initial temperature is given at t=0 s .


f(t) = 17.60e^(-0.0399* 0) + 20\\\\f(t) = 37.60^o\ C

Therefore, the initial temperature of the object is 37.60° C.

Hence, this is the required solution.

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