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A syringe has a fine needle with an inside diameter of 109μm. The barrel has a diameter of 2.22cm and is filled with water. Calculate the velocity of water as it squirts horizontally from the needle if you apply a force of 3.24N onto the plunger. (Hint: you may approximate the area of the barrel to be much larger than the area of the needle).

User Gakhov
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2 Answers

5 votes

Final answer:

The velocity of water squirting from the needle of a syringe can be calculated using Bernoulli's equation and the conservation of flow rate by considering the force applied, and the cross-sectional areas of both the barrel and the needle.

Step-by-step explanation:

To calculate the velocity of water as it squirts from the needle of a syringe when a force is applied, we can use the principle of conservation of flow rate and apply Bernoulli's equation. For a syringe, the conservation of flow rate tells us that the product of cross-sectional area and velocity is the same at any two points along the flow. Since the areas of the barrel and the needle are different, the velocities will also be different.

To find the velocity, we first calculate the area of the needle's opening (Aneedle) and the area of the barrel's cross-section (Abarrel). The force applied to the plunger (F) creates pressure that pushes the water through the syringe. Using Aneedle = π * (Dneedle/2)2 and Abarrel = π * (Dbarrel/2)2, and the relation F = Abarrel * P, where P is the pressure, we can derive the velocity of water exiting the needle (Vneedle) by Vneedle = Abarrel * Vbarrel / Aneedle.

The velocity of the barrel can be assumed to be negligible due to the large cross-sectional area compared to the needle, thus Vbarrel is practically zero, and the velocity Vneedle can be primarily determined by the pressure created by the applied force.

User Olenka
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4 votes

Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s

Step-by-step explanation:

Given that;

inside diameter = 109μm

barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m

force fair = 3.24 N

We know that the inside diameter is neglected; from the Bernoulli's equation

so

P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside

p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel

Fair = 1/2painv²outside . Abannel

therefore

3.24 = 1/2(1000) v²outside (πr²)

3.24 = 1/2(1000) v²outside (π × (0.0111)²

3.24 = 0.1935 v²_outlet

v²_outlet = 3.24 / 0.1934

v²_outlet = 16.7441

v_outlet = √16.7441

v_outlet = 4.09196 m/s

Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s

User Vosmith
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