Question

In the reaction of: ????2O4 (g) ⇌ 2????O2(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of ????2O4 = 0.0500 ????. What are the equilibrium concentrations of ????2O4 and ????O2 under these conditions?

Answer 1

[N₂O₄] = 0.00411 M

[NO₂] = 0.0918 M

Step-by-step explanation:

In the reaction of: N₂O₄(g) ⇌ 2 NO₂(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of N₂O₄ = 0.0500 M. What are the equilibrium concentrations of N₂O₄ and NO₂ under these conditions?

Step 1: Given data

Initial concentration of N₂O₄: 0.0500 M

Equilibrium constant (Kc): 0.513

Step 2: Make an ICE chart

N₂O₄(g) ⇌ 2 NO₂(g)

I 0.0500 0

C -x +2x

E 0.0500-x 2x

Step 3: Find the value of "x"

The equilibrium constant is:

Kc = [NO₂]² / [N₂O₄]

0.513 = (2x)² / (0.0500-x)

4x² + 0.513 x -0.02565

We solve for x and we get x₁ = 0.0458942 and x₂ = −0.558894 (neglected).

Step 4: Calculate the concentrations at equilibrium

[N₂O₄] = 0.0500-x = 0.00411 M

[NO₂] = 2x = 0.0918 M