Question

The mercury level in the open arm of an open-end manometer is 106 mm above the level in the arm connected to a tank of gas. If the barometric pressure is 0.958 atm, what is the pressure (in torr) of the gas in the tank?

Answer 1

`833.72\ \text{torr}`

Step-by-step explanation:

`P_g` = Pressure of gas =
`106\ \text{mmHg}`

`P_a` = Atmospheric pressure = 0.958 atm

Absolute pressure is given by

`P=P_g+P_a`

`\Rightarrow P=(106)/(760)+0.958`

`\Rightarrow P=1.097\ \text{atm}=1.097* 760=833.72\ \text{torr}`

The pressure of the gas in the tank is
`833.72\ \text{torr}`