Answer:
[OH⁻]= 6.76*10⁻¹² M
pH= 2.83
[H₃O⁺]= 1.48*10⁻³
Step-by-step explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution that indicates the concentration of hydroxyl ions [OH-] present in a solution. The pOH is defined as the logarithm of the concentration of OH- ions, with the sign changed:
pOH= -log[OH⁻]
In this case, pOH= 11.17. So:
11.17= -log [OH⁻]
Solving:
-11.17=log [OH⁻]
10⁻¹¹ ¹⁷= [OH⁻]
6.76*10⁻¹² M= [OH⁻]
pH, short for hydrogen potential, is a parameter that indicates the concentration of hydrogen ions [H⁺] or [H₃O⁺] that exist in a solution and is calculated as the logarithm of the concentration of H⁺ ions, with the sign changed:
pH= -log[H⁺]= -log[H₃O⁺]
The relationship between pH and pOH can be established by the expression:
pH + pOH= 14
In this case, being pOH=11.17:
pH + 11.17= 14
and solving you get:
pH= 14 - 11.17
pH= 2.83
Finally, replacing this value in the definition of pH:
2.83= -log [H₃O⁺]
and solving you get:
-2.83= log [H₃O⁺]
10⁻² ⁸³= [H₃O⁺]
1.48*10⁻³= [H₃O⁺]