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Suppose that two fair dice are rolled. Find the probability that the number on the first die is a 6 or the number on the second die is a 4.

User Killogre
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3 votes

Answer:


Probability = (1)/(36)

Explanation:

Given

Two fair dice

Required

Determine the probability that the outcomes is 6 on the first and 4 on the second

First, we need to write out the sample space of both:


S_1 = \{1,2,3,4,5,6\}


n(S_1) = 6


S_2 = \{1,2,3,4,5,6\}


n(S_2) = 6

Where S1 represents the first and S2, the second

The probability of outcome of 6 on the first is:


P(6) = (n(6))/(n(S_1))


P(6) = (1)/(6)

The probability of outcome of 4 on the second is:


P(4) = (n(4))/(n(S_2))


P(4) = (1)/(6)

So, the required probability is then calculated as:


Probability = P(6) * P(4)


Probability = (1)/(6) *(1)/(6)


Probability = (1)/(36)

User Verpous
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